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5^{x-3}\cdot 3^{2x-8}=225
5^{x-3}\cdot 3^{2(x-4)}=225
5^{x-3}\cdot (3^2)^{x-4}=225
5^{x-3}\cdot 9^{x-4}=225

In view of getting same exponent on both terms on left hand side, divide 5 each side :
\dfrac{5^{x-3}\cdot 9^{x-4}}{5}=\dfrac{225}{5}




Since the bases are equal, exponents also must be equal :
0 0 0
notice, 9 is not affected, you're not dividing 5 by 9.
ok.. i got it....:)
thank u so much...
sweet :)
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