# A car initially at rest, picks up a velocity of 72km/hr in 20 seconds. if the mass of the car is 1000kg find force developed by its engine

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by sahithu

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by sahithu

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Acceleration, a = 72/3.6 * 20 m/s^2 = 1 m/s^2

Therefore, force developed by the engine, F = m*a = (1000*1) =**1000 N**

Therefore, force developed by the engine, F = m*a = (1000*1) =

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Mass of the car is 1000 kg

and acceleration of the car is 72km/hr for 20 second.

for converting m/s

1km/hr =__5 __m/s

18

72*__ 5 __ = 20 m/s

18

20m/s in 20 second

so acceleration =__20 __m/s = 1 m/s^2

20 s

force F = ma

m= 1000kg

a = 1 m/s^2

⇒ F = ma

⇒ = 1000 * 1

⇒__ F = 1000 N __

and acceleration of the car is 72km/hr for 20 second.

for converting m/s

1km/hr =

18

72*

18

20m/s in 20 second

so acceleration =

20 s

force F = ma

m= 1000kg

a = 1 m/s^2

⇒ F = ma

⇒ = 1000 * 1

⇒