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α and β are zeros / roots of 2 x² - 3 x + 7

So the sum of the roots = α + β = - (-3/2) = 1.5 and the product of the roots = α β = 7 / 2 = 3.5

Given f(x)=2x²-3x+7 ,α andβ are zeros of the equation find 1/α+1/β=β+α = sum of roots/product of roots point as 1st αβ on comparing given equation with ax²+bx+c=0 ,a=2 ,b=-3 and c=7 (α+β) sum of roots=-b/a= -(-3/2)⇒3/2 (αβ) product of roots=c/a=7/2 put the value in 1st 1/α+1/β= 3/2 ⇒3/7⇒0.42 7/2