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For 9 ohms , connect two in parallel and the third in series with the earlier combination of two resistors . thus first two resistors in parallel, 1/6 +1/6 = 1/r r = 3 ohms------ connect in series with third resistor R =3+6 ohms = 9 ohms for 4 ohms - two resistances in series and the third one in parallel with the combination of earlier two resistances.

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If we arrange n resistors of value R ohms in series, the effective resistance: n R ohms if we arrange n resistors of value R ohms in parallel, then the effective resistance: R / n ohms

for getting effective resistance of 4 ohms from 6 ohm resistors, we can put two resistors in series, and their equivalent resistance = 12 ohms. Then connect the third resistance of 6 ohms in parallel. equivalent resistance = 12 * 6 /(12+6) = 4 ohms. =============

if we connect two resistors in parallel then effective resistance = 6/2 = 3 ohms. We connect the third resistance in series. The effective resistance: 3 + 6 = 9 ohms