Answers

2015-04-27T11:29:03+05:30
(c) 25200 is the correct answer.
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2015-04-27T18:53:41+05:30
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C3 x 4C2) = 7 x 6 x 5 x 4 x 3 3 x 2 x 1 2 x 1 = 210. Number of groups, each having 3 consonants and 2 vowels = 210. Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 5 x 4 x 3 x 2 x 1 = 120. Required number of ways = (210 x 120) = 25200.
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