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A farmer moves along the boundry of a square field of side 10 m in 40 sec. what will be the magnitude of displacement of the farmer at the end of 2 minutes

20 sec from his initial position?


So his speed=distance/time=10/40=0.75 m s-1
time taken t=2 min 20 sec=2*60+20=120+20=140 s
so distance covered is 140(0.75)=105 m
As it is square field 
the man completes 2 rounds and then covers 25 m more
so the final displacement is 11.180339887498948482045868343656 
1 5 1
its wrong...
now its correct sure!!!
no its wrong
SQ ABCD [fig.]
he starts from A and will reach the opp. corner i.e. C  in 140 sec.
 displacement = AC
                 AC =14.14m
0 0 0
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