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2015-04-29T00:54:39+05:30

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Atomic weight of metal M = 56
in an oxide,  metal is  70% by mass        and so  oxygen is 30% by mass.
let there be  n atoms of  oxygen per 1 atom of metal.
Then  proportion of the masses of metal and oxygen : 
             56 :  n * 16  = 70  : 30
           16 n = 56 * 30 / 70
                 n = 24/16 = 1.5

There are two atoms of metal for 3 atoms of Oxygen.:        M2 O3

2 5 2
2015-04-29T10:38:56+05:30
Ans: M2O3 Ratio of moles of metal and oxide: M : O 70/56 : 30/16 1 : 1.5 2 : 3 Hence formula is M2O3
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