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2015-04-28T15:42:03+05:30

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Recall the identity a^3-b^3=(a-b)(a^2+ab+b^2)

The given expression is same as
\dfrac{(x-y)^2}{(x-y)(x^2+xy+y^2)}

Cancel the common factor x-y top and bottom and get
\dfrac{x-y}{x^2+xy+y^2}
3 3 3
2015-04-28T15:45:07+05:30
=x^2+y^2-2xy/x^3-y^3
=-2

1 5 1
Plz show the working
just cancelling we cant show there