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Sample space{HH,HT,TH,TT}
head on both coin{HH}
Total no of sample space=4
no. of fav caeses=1
probability of getting head on both coin=total no of fav cases/total no of sample space=1/4

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When 2 coins re tosssed th probability of getting head on both coinis no of favourable outcomes of E by all possible outcomes 
there fore answer is 1by4

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