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◻➕◻➕◻➕◻➕◻=30 Fill the boxes using (1, 3, 5, 7, 9, 11, 13, 15) U can also repeat the numbers..This question came in UPSC Final Exams held in Dec '13...... You will be glad to note that only Gaurav Agarwal could solve it.

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The sum of three odd numbers gives an odd number So, the sum of 3 given odd numbers doesnt results 30 So, it is an impossible factor here we can't use 3! too because 3! [3×2×1] results a even number 6 so we cant use it. If there will be an allowance of factorials, then the answers will be 3!+1+5+7+11=30 3!+1+3+7+13=30

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Gaurav Agrawal (IAS) answered very
intelligently in 2014 using his imagination as 3! + 3! + 3! + 3! + 3! = 30
This question is asked so many
times.. all credit goes to him. The following ways are my suggestions.
I can answer this question in many ways using the factorial function. 3 ! =>
3 factorial. it is a mathematics operator like + or /.. 3 ! = 3 * 2 * 1 = 6.
3! + 1 + 3 + 9 + 11
= 30
1 + 5 + 7 + 3! + 11
= 30
3! + 3! + 3! + 11 + 1
= 30
3! + 3! + 11 + 5
+ 1 = 30
11+ 1 + 1 + 3! + 11
= 30
15 + 3 + 3 + 3 + 3!
= 30
13 + 1 + 1 + 9 + 3!
= 30
13 + 1 + 3 + 7 + 3!
= 30
13 + 5 + 3 + 3 +
3! = 30

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You need one operator for which the result is an even number with an input
being an odd number. Factorial is one. Probably there are other
operators too.