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A vector is given by 6Î -8ĵ +4

Find the vector which is antiparallel to the given vector having magnitude of sqrt 58 units.


The vector is  \sqrt{ \frac{58}{116}} (-6i+8j-4k)= \frac{ (-6i+8j-4k)}{ \sqrt{2} }
2 4 2
Thanks but can you write the full solution please ?
u need not use the sqrroot sign
Anti parallel means negative of the given one.i.e.,(-6i+8j-4k)
the required vector=(-6i+8j-4k)*(58)^1/2/[((-6)^2+8^2+(-4)^2)]^1/2
therefore,vector anti parallel to given vector=(-6i+8j-4k)/(2^1/2)
1 5 1
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