Answers

2015-05-04T14:12:45+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
I suppose we have to solve the given non-linear logarithmic equation.

solving the given equation:

Log\frac{0.9}{x}=4.15\ Log\ \frac{1.1}{1-x}

gives  x = 0.218198  approximately.

=============================
Log\frac{0.9}{x}=4.15\ Log\ \frac{2(1-0.45)}{1-x}\\\\Log\ 0.9-Log(x)=4.15*Log\frac{1.1}{1-x}\\\\log\ 0.9-log(x)=4.15*Log1.1-4.15*log(1-x)\\\\-0.2175 -log(x)=-4.15*log(1-x)\\\\let\ x=y^{4.15}\\\\-0.2175-4.15log(y)=-4.15\ log(1-y^{4.15})\\\\log(1-y^{4.15})-log(y)=0.05242\\\\log\frac{1-y^{4.15}}{y}=0.5242\\\\\frac{1-y^{4.15}}{y}=10^{5242}=1.12828\\\\y^{4.15}+1.12828y=1

y=\frac{1}{y^{3.15}+1.2828}
This equation can be recursively used to find y.  After finding y to the required precision, we find  x = y^4.15..

for example:  
y = 0.1    =>  y =

1 5 1