# The length of a rectangle exceeds in its width by 4m. if its perimeter is 40m, find its dimensions.?

2
by applle

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by applle

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where x-length

y-breadth

acc to question , x=y+4

substituting in perimeter equation,

40=2(2y+4)

2y=16

y=8m

hence x=y+4

8+4

=12m

the dimensions are thus 8m and 12 m .

The Brainliest Answer!

Then, length = (x+4)m

Perimeter=40m.

Putting value of l and b in equation (i) we get,

⇒40=2(x+4+x)

⇒40=2(2x+4)

⇒40/2=2x+4

⇒20-4=2x

⇒16=2x