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Perimeter of rectangle is 2(x+y) where x-length y-breadth acc to question , x=y+4 substituting in perimeter equation, 40=2(2y+4) 2y=16 y=8m hence x=y+4 8+4 =12m the dimensions are thus 8m and 12 m .

Let width of the rectangle be x metres, Then, length = (x+4)m Perimeter=40m. Perimeter of a rectangle = 2(l+b)......(i) Putting value of l and b in equation (i) we get, ⇒40=2(x+4+x) ⇒40=2(2x+4) ⇒40/2=2x+4 ⇒20-4=2x ⇒16=2x ⇒x=8 Therfore, breadth = x = 8m and length = x+4=8+4=12m