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You may use \tanh^{-1}(x)=\frac{1}{2}\ln\frac{1+x}{1-x} to simplify the work slightly :





Now take the derivative 

2 5 2
we did tanh^-1(3x-2) in previous problem right ?
oh sorry i messed up i got it now !
it would be a good exercise to work it using chain rule and see both answers match
dont mind, but r u a student or sir ?
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