Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

yield
for one acre plot = random variable x
μ = mean of the distribution for yield = E (X) = 662 kg
standard deviation = σ = 32 kg

Normal distribution variable = X = (x - μ)/σ
cumulative probability function of the normal distribution:
F(X ) = P (X
<= x)

Probability p of yield x being in the range 600kg and 750kg = P(600 ≤ x ≤ 750)

p = P[ (600 - 662)/32 ≤ X ≤ (750 - 662)/32 ]
= P [ -1.9375 ≤ X ≤ 2.75 ]
= P( X ≤ 2.75) - [ 1 - F( X ≤
1.9375) ]

=> p = F (2.75) + F (1.9375) - 1

Look up these values in normal distribution function
tables. I have the two values as below:

p = 0.997 + 0.973
- 1 = 0.97 approximately.

You need to know how to read and interpret the values in the table.

0.97 : This is the probability with which a
randomly selected plot may produce a yield in the given range.

Number of plots we have = N = 1000 plots = data
sample size.

Number of plots, that are likely to produce yield in the given range = N * p = 1000 * 0.97 = 970 plots.