How molecules of are present in 1 litre air containing 80% volume of at STP?

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molecules of what?
ita air to it will be molecules of O2. At S.T.P., 1 mole of any gas = 22.4 Litres(It's a given. I assume you know thisone.) Therefore, 1 Litre of a gas = 1/22.4 = 0.0446 moles Out of these 0.0446 moles, 80% is Oxygen gas. Number of moles of Oxygen gas = 0.0446 x 80% = 0.0446x 80/100 = 0.0357 moles. 1 mole of any gas = 6.02 x 1023 units (This is also a given, known as the Avagadro's constant.) Therefore, 0.0357 moles = 0.0357 x 6.02 x 1023 = 2.15 x 1022 molecules of O2 is present in 1 litre air

Answers

2014-05-09T15:05:48+05:30
its air to it will be molecules of O2. At S.T.P., 1 mole of any gas = 22.4 Litres(It's a given. I assume you know thisone.) Therefore, 1 Litre of a gas = 1/22.4 = 0.0446 moles Out of these 0.0446 moles, 80% is Oxygen gas. Number of moles of Oxygen gas = 0.0446 x 80% = 0.0446x 80/100 = 0.0357 moles. 1 mole of any gas = 6.02 x 1023 units (This is also a given, known as the Avagadro's constant.) Therefore, 0.0357 moles = 0.0357 x 6.02 x 1023 = 2.15 x 1022 molecules of O2 is present in 1 litre air
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2014-05-11T22:32:07+05:30
The answer is 2.15*10^22 molecules of O2 which are present in 1 lit of air.
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