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Formula is last term =first term -(n-1)difference 4=a+(2)d equation 1 -8=a+8d equation 2 by solving both we get d=-2 then by substituting that in any of the equation we get the first term as 8 therefore the term which is 0 is 5th term

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given 3rd term = 4 i.e, a+2d=4 ---- 1 and 9th term = -8 i.e., a+8d=-8 ------------- 2 by by subtacting 1 and 2 we get, a+2d = 4 a+8d = -8 - - + ---------------- -6d = 12 --------------- so, d = -12/6 d = -2 substitute it in (1) we get, a+2(-2) = 4 a = 4+4 =8 a=8

here we get a=8

2nd term = a+d = 8+(-2) = 8-2 = 6 3d term = a+2d = 8+2(-2) = 8-4 = 4 4th term = a+3d = 8+2(-3) = 8-6 = 2 5th term = a+4d = 8+2(-4) = 8-8 =0 6th term = a+5d =8+5(-2) = 8-10 = -2 .......

so the series we got is 8,6,4,2,0,-2..... here we get zero at 5th place so, 5th number in the series is 0