A particle is pushed along a horizontal surface in such a way that it starts with a velocity of 12m/s.Its velocity decreases at a uniform rate of 0.5m/s^2. [a] Find the time it will take to come to rest. [b] Find the distance covered by it before coming to rest?

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2015-05-18T05:23:18+05:30

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U = 12 m/s
a = - 0.50 m/s/s

v = 0
     v = u + a t
  => t = (0 - 12 ) / (-0.50) =  24 sec

  s = u t + 1/2 a t²  = 12 * 24  -  1/2 * 0.50 * 24²
       = 144 meters

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