Answers

2015-05-07T14:50:56+05:30
Volume = (pi/3)H(A2 + AB + B2).
Surface Area = pi(A + B)sqrt[(B-A)2 + H2].................
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2015-05-07T15:00:10+05:30
1/3πh(r²+R²+rR) ⇒ volume
π(R+r)l ⇒ curved surface area, where l = √h²+(r-R)²
πl (r+R)+ πR+ πr ⇒ total surface area
h be height, l be slant height and r and R the radii of the ends (r>R) of the frustum of cone

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