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## Answers

**⇒ In the given figure , the following things should be noted -**

__GIVEN ;-__

**⇒ ABCD is a rhombus**

**⇒ Diagonals of the rhombus are AC and BD**

**which intersect at O.**

**⇒**

TO PROVE ;-

TO PROVE ;-

__''The circle drawn with any side of a rhombus as diameter''__**⇒ ∠ AOB = ∠ BOC = ∠ COD = ∠ AOD = 90 [ Diagonal of the rhombus bisect each other at 90°]**

PROOF ;-

PROOF ;-

**⇒ All this diameters passes through O. {**

Now in the given four circles , we have four diameters - AB , BC , CD , DA.

Now in the given four circles , we have four diameters - AB , BC , CD , DA.

**Angles in a semi circle is right angle**}

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**⇒**

**Therefore by the above information , we proved that the circles described in the four sides of a rhombus as a diameter, pass through the point of intersection of its diagonal.**