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A bullet fired into a fixed target loses half of its velocity after penetrating 3cm. How much futher it will penetrating before coming to rest assuming

that it faces constant resistance to motion.


Let initial velocity of the bullet = u
After penetrating 3 cm its velocity becomes = u/2
From v2 = u2 - 2as
(u/2)2 = u2 - 2as
Thus, a  = u2/8
Let further it will penetrate through distance x and stops at some point
.0 =  (u/2)2 - 2 (u2/8)x
Therefore, x = 1 cm
0 0 0
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