Answers

2015-05-08T17:00:48+05:30
S=ut+\frac{1}{2}at^2

First 10 seconds :
At t=0, the velocity of particle is 0 as it is starting from rest. Therefore, u=0 and the distance travelled is given by 
X=0*10+\frac{1}{2}a*10^2=50a

Next 10 seconds :
By the end of 10th second, the particle's velocity reaches 10a. Therefore, u=10a and the distance travelled is given by
Y=10a*10+\frac{1}{2}a*10^2=150a

Dividing gives
\frac{Y}{X}=\frac{150a}{50a}=3

\implies\boxed{Y=3X}
0