Log in to add a comment

## Answers

**⇒ In the given circle , the following things should be noted-**

__Given :-__

**⇒ O is the centre of the circle**

⇒ AB is the chord .

⇒ ACB is the major sector { Because it lies in the larger portion of the circle }

⇒ADB is he minor sector { As it lies in the smaller portion of the circle }

⇒

__TO PROVE ;-__

⇒''

**Prove that the angle formed by a chord in a major segment is acute''**

**⇒**

**PROOF :-**

**⇒**

**We know that**

**∠ACB is one of the angle of the major sector.**

**The angle subtended by an arc of a circle at its centre is twice the angle subtended by it at any point on the remaining circle''**

So remember the theorem :- ''So remember the theorem :- ''

⇒ Hence by this above statement we get as ,

⇒

__∠__**{ where ACB is the major sector and ∠ACB is the angle subtended by it in another segment. }**

__AOB = 2∠ACB__Hence ,

__2∠ACB < 180°__

⇒ We get the result as

**∠ACB < 90°**

⇒So hence

**∠ACB is an acute angle because it is lesser than 90 degree.**

⇒

**Hence proved.**.