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*1st Method:*

Sn (Sum of the 'n' numbers) = n/2 (2a+(n-1)d)Sn (Sum of the 'n' numbers) = n/2 (2a+(n-1)d)

*there given last no. is 250, so the no.of even numbers here is 250/2 i.e., 125*

*i.e., n=125, a (1st number) = 2, l (last number) = 250*

*then,*

*Sn = n/2 (a+l)*

*= 125/2 (2+250)*

*= 125×252/2*

*= 125(126)*

*= 15750*

*therefore, the sum of all the even no.s upto 250 is 15750*

2nd Method:

Sn = n/2 (2a+(n-1)d)

we got n= 250/2 = 125, a=2, d (common difference) = 2

Sn = 125/2 (2(2)+(125-1)2)

= 125(4+248)/2

= 125(252)/2

= 125(126)

= 15750

hence,2nd Method:

Sn = n/2 (2a+(n-1)d)

we got n= 250/2 = 125, a=2, d (common difference) = 2

Sn = 125/2 (2(2)+(125-1)2)

= 125(4+248)/2

= 125(252)/2

= 125(126)

= 15750

hence,

*the sum of all the even no.s upto 250 is 15750*### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

This is an ap with common diff.. 2

so use formula n(a1+an)/2

on this ap there will be 125 terms

so ..n=125

therefore

Sn=125(2+250)/2

=(125*252)/2

=15750

so use formula n(a1+an)/2

on this ap there will be 125 terms

so ..n=125

therefore

Sn=125(2+250)/2

=(125*252)/2

=15750