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The water in a rectangular reservoir having a base 80m by 60m is 6.5m deep. in what time can the water be emptied by a pipe of which the cross-section is a

square of side 20cm, if the water runs through the pipe at the rate of 15Km per hour?


The Brainliest Answer!
Vol.of water= 80*60*6.5
area of the cross section of the pipe= 20*20cm²= .2 *.2 m²
distance the water has to flow so that the tank would be emptied
                             = vol.of the water/area of the cross section
                             =80*60*6.5/(.2*.2) = 78000m=78 km
now,we know that v=d/t
so,t= d/v = 78/15= 5.2 hours

2 5 2
wat 4?u will say and mark other's as the brainliest..
it's ok.. srry for being rude..
its ok
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