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A body covered a distance of x meter along a semicircular path.Calculate the magnitude of displacement of the body,and the ratio of distance to



Let the radius of the semi-circular path be r

So, the distance covered by the path is πr=x m⇒  r=x/π
 And the displacement = 2r=2Xx/π

So the ratio of distance to displacement = x:2x/π=π:2x
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we know that circumference of a circle is 2.pi.r
so,that of a semicircle = pi.r
it's given that,distance traveled / pi.r.= x 
hence, r = x/pi
and,as we know, displacement = diameter = 2.r = 2*x/pi
thus, distance:displacement = x : 2x/pi = pi : 2x

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