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A gaseous alkane requires five time its volume of oxygen under the same conditions for comolete combustion. The molecular formula of the alkane is?



General equation for the complete combustion of alkane is
CnH2n+2 + (3n+1)/2 O₂ = nCO₂ + (n+1)H₂O
here the co-efficients of the equation represent the relative mole no.
for gases at NTP 1 mole occupies 22.4 litre
so relative mole no can b considered as relative volume
here (3n+1)/2 = 5
so n = 3
& the alkane is C₃H₈
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