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The laws of motion are:

v = u + a t --- (1) s = u t + 1/2 a t² --- (2) v² = u² + 2 a s --- (3)

s = (v + u) t / 2 --- (4)

since a constant force acts on the body, the acceleration of the body is constant. v = 63 kmph = 63 * 5/18 m/sec = 35/2 m/sec u = 45 kmph = 45 * 5/18 = 25/2 m/s

we apply the equation of motion (4), s = (35/2 + 25/2) * 10 / 2 m = 150 meters

we could ALSO find acceleration by equation (1) and then find the distance / displacement using equation (2) or (3).

Here given, u = 45 km/hr ; v = 63 km/hr and t = 10 s u = 45 *5/18 m/sec = 12.5 m/sec v = 63 * 5/18 m/sec = 17.5 m/sec Now by first equation of motion, we will take out acceleration v = u + at => at = v - u => a = (v - u)/t => a = (17.5 - 12.5)/10 = 5 / 10 m/sec² = 0.5 m/sec² now we have got a = 0.5 m/sec² by third equation of motion, v² - u² = 2as => s = (v² - u²) / 2a => s = {(17.5)² - (12.5)² } / 2*0.5 => s = {306.25 - 156.25} / 1 => s = 150 m