Answers

2015-05-18T01:17:24+05:30
2KClO₃       =       2KCl  +    3O₂
2(38+35.5+48)                      3(2×16)
=243                                    =  96
So from 243g KClO₃  96g  O₂ is produced 
so (96/243)×50 g O₂ = 19.75g O₂ is produced from 50g KClO₃

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