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Solution : Let the time taken by car B to Overtake Car A = t Therefore the total distance Car B has to travel = Initial Distance (100 m) + distance travelled by Car A in t sec Distance Traveled by Car A in t sec = velocity of Car A * t (Because velocity = distance / time ) . = 50t Therefore the total distance Car B has to travel = 100 + 50t. We know that , S = ut + 1/2at^2 u=velocity of car B and a= accelaration Of car B 100 + 50 t = 50 t + 1/2 * 2* t^2

100 = t^2 => t^2 = 10 ^ 2 => t = 10 sec . hence The time taken by the car B to overtake Car A = 10 seconds

B..................................A........................................... <----------------------------------><------------------------------------------> 100m s let car A travail s meter in time t , then s = 50t ..................(1) car B travail (s +100) meter in time t s+100 = 50t + 1/2*2*t^2 ..............................(2) put the value s from equation (1) 50t + 100 = 50t + 1/2*2*t^2 t^2 = 100 t = 10 or -10 since time can not be negative ,so t = 10Sec.