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If the polynomial(3xcube + axsquare + 3x +5) and (4xcube + xsquare -2x + a) leave the same remainder when divided by x-2 then find the value of a and also

remainder in both case


After dividing 3x³+ax²+3x+5 by x-2
and 4x³+x²-2x+a by x-2
remainder will be 2ax+ 35 and 32 +a
according to question,
 2ax+ 35=32+a

then remainder will be   (35-64x)÷1-2x
0 0 0
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