# IN RIGHT TRIANGLE ABC,C IS RIGHT ANGLE.c=3 AND a+b=root 17.COMPUTE AREA OF THE TRIANGLE?

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from pythagoras` theorem

a² + b² = c²

⇒ (a+b)² - 2ab = 3² = 9

⇒√17 ² - 2ab = 9

⇒17 - 2ab = 9

⇒2ab = 8

⇒ ab = 4

area of the triangle is (1/2 × height ×base)

= 1/2×ab

= 1/2 × 4

= 2 square units

The Brainliest Answer!

Since ABC is a right angled triangle,

From Pythagorus Theorem,

Therefore,

c² = a²+b²+2ab - 2ab

c² = (a+b)² - 2ab

Substituting value of c and (a+b),

3² = (√17)² -2ab

9 = 17 - 2ab

2ab = 17-9

2ab = 8

ab=8/2

Area of triangle ABC = 2 sq. units.