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In a straight contest , the loser polled 42% votes and lost by 14400 votes . Find the total no. of wath votes polled . If the total no. number of eligible

voters were 1 lakh , find wahat percentage of voters did not vote .

Let the total no. of votes be x. ⇒Loser gets 42% of x votes=42x/100 votes. ⇒Winner gets 100%-42%=58% of x votes=58x/100 votes. Now , margin by which loser lost=14400. Therefore, difference between winner's and loser's votes is 14400. ⇒Given , 58x/100-42x/100=14400 ⇒(58x-42x)/100=14400 ⇒16x/100=14400 ⇒x=14400*100/16 (by cross multiplication) ⇒x=90000. =============================================(Part 1 solved ) Hence the total no of votes polled is 90000. No . of eligible voters=100000 ⇒No. of voters who didn't vote=100000-90000=10000. ⇒Percentage of voters who didn't vote=10000/100000*100 % =10% ================================================(Part 2 solved) Ans:The number of votes polled is 90000. 10% voters didn't vote. (I'm thinking why so)

Loser got 42% votes, that means, Winner got 58% votes. Difference is 16% So, 16% of total votes polled = 14400 Let the no of votes polled = x 0.16x = 14400 x = 90000 that means, 90000 votes polled. Eligible voters = 100000 No. of voters did not vote = 100000 - 90000 = 10000 Which is 10% of the total.