The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 × 10^5 ms–1 . If the hockey ball of mass 0.1 kg is moving with this velocity, calcualte the wavelength associated with this velocity.
Ncert solutions for Class 11th Chemistry Part - 1 Chapter 2 Exercise 60

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Answers

2015-05-22T15:06:46+05:30
Wavelength associated with this velocity will b 
λ = h/p ( de Broglie equation ) ( h = Planck`s constant , p = momentum )
now momentum of the ball is
mass × velocity = 0.1×4.37 × 10⁵ = 4.37 ×10⁴ kgms⁻¹

h = 6.027 × 10⁻³⁴ 
so λ = (6.027 × 10⁻³⁴)/(4.37 ×10⁴) = 1.38 ×10⁻³⁸ m
wavelength associated with this velocity will b = 1.38 ×10⁻³⁸ m

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