If the photon of the wavelength 150 pm strikes an atom and one of tis inner bound electrons is ejected out with a velocity of 1.5 × 10^7 m s–1, calculate the energy with which it is bound to the nucleus.
Ncert solutions for Class 11th Chemistry Part - 1 Chapter 2 Exercise 54

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Answers

2015-05-22T17:06:04+05:30
E=6.6*10^-34*3*10^8/1.5*10^-10=1.32*10^-15
Energy of ejected electron 
E=1/2mv2
=1/2*9.1*10^-31*(1.5*10^7)2
=1.02*10^-16
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