Answers

2015-05-23T11:30:33+05:30
FIRST WE FIND TOTAL RESISTANCE
IN SERIES,        TOTAL R=R₁+R₂.........RN
  HERE,                   TOTAL RESISTANCE=10Ω+15Ω=25Ω
ALSO WE KNOW THAT      Δ V=IR (ΔV IS POTENTIAL DIFFERENCE)
 HERE                I=? 
                          R=25Ω
                         Δ V=6 volts
PUTTING IN THE EQUATION
                                   6=I×25
                                      I=6/25À

1 5 1
I am sorry ...i have got one doubt ....but in question it is asked about "how can the values of current passing through them compared?" so my doubt is ..that. i have understood what u have done..but i still don't get the comparing part...#Kshitijmanitiwari
2015-05-24T09:09:10+05:30
In a series connection 
total resistance is equal to R=r1+r2+r3+r4+...............+rinfinity
 total resistance offred by object             =10Ω+15Ω=25Ω
Change in potential diffrenece=IR
   6=I×25
so I=6/25

                      
                 

                                  
1 5 1
I am sorry ...i have got one doubt ....but in question it is asked about "how can the values of current passing through them compared?" so my doubt is ..that. i have understood what u have done..but i still don't get the comparing part...#Rajusetu