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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

If the wire is bent to form a square,then the resistance of the side of the square=20/4=5 Across the diagonal, first calculate the resistance through the two sides that is R1=5+5=10 then through the diagonal,R2=root over of(5^2+5^2)=5*root2 as R1 and R2 are parallel to each other, 1/R=1/R1+1/R2 1/R=1/10+1/5*root2 1/R=(root2+root2)/10*root2 1/R=2*root2/10*root2 root2 cancelled in both,hence 1/R=2/10 1/R=1/5 R=5 Hope it helped you.

Sorry didn't understand "as R1 and R2 are parallel to each other,"...? how? ..please..could u explain how?.. #SweetShreya

actually i didn't understand the question " What is the resistance across a diognal of the square?" ....could to please make me understand ..the across of diagonal part....