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present age: let the age of father be x yr let the age of son be y years given: x+y=54 ----1st equation 6 yrs back: fathers age=x-6 sons age = y-6 given: x-6=4(y-6)+2 ---> x-6=4y-22 --->x-4y= -16 -----2 nd equation by solving 1st and 2nd equations, we get y=14 years and x= 40 years. hence the age of son and father are 14 and 40 years respectively.

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Answer : Let Present age of Father (in Years)= x and Present age of Son (in Years)= y According to Question, x + y = 54 or x = 54 - y ---- 1st Before 6 years , Fathers age = x+6 Sons Age = y+6

x -6 = 4(y -6) + 2 or x - 6 = 4y - 24 + 2 x = 4y - 22 + 6 x = 4y - 16 Using Ist , we get 54 - y = 4y - 16 54 + 16 = 4y + y 70 = 5y or y = 14 Substitute Value of y in Ist we get , x = 54 - 14 x = 40

Hence Present age of Father = 40 years and Present age of Son = 14 years