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Father's age is three times the sum of ages of his two children. After 5 years, his age will be twice the sum of ages of two children. Find the age of

(use only 2 variables to find the age)


Let the age of two children be x and y.
father's present age is 3(x+y).
age of children after 5 years= x+5+y+5
                                        = x+y+10
age of the father after 5 years= 2(x+y+10) or 3(x+y)+5
                        2x+2y+20 = 3x+3y+5
                        2x-3x + 2y-3y= -20+5
                                    -(x+y) = -15
                                     x+y = 15
                  3(x+y) = 3(15)
therefore, present age of father is 45.

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