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A particle has displacement12 cm towards east and 9cm towards north and then 6cm vertically upward. find the magnitude of sum of these displacement



If we draw a rough diagram we get a right angled triangle with sides 12 cm and 15 cm.
displacement is shortest distance,so,here displacement is hypotenuse.
       =19.2 cm
1 5 1
√261=16.15m Phytagorilla theorem.
0 0 0
r Horizontal distance travelled will be √(12^2+9^2)=15
Now as vertical displacement is 6 cm,
Total displacement will be √(15^2+6^2)=√261 cm
An alternative solution is here first we apply pythagoras thm. on 12 n 9cm so that v
get 15 as resutant... afterward u know that body is 6
cm vertically upward so here we will apply pythagoras
on 15 and so that we get an 3-D image whose
resultant will be √261
i hope you will have got it now adesh if need more help then you can ask
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