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A motorcycle drives from place AtoB with a uniform speed of 30 km/h and returns from place BtoA with a uniform speed of 20km/h find his average speed.



As we know the cycle travels from A to B and comes back from B to A so let the distance be x km.

Then, given speed₁ = 30 km/hr     and speed₂ = 20 km/hr
               therfore, time₁ = d/s = x/30  and time₂ =x/20
      so Average speed = total distance/total time
                                 =x + x/ x/30 + x/20
                        on solving i get 24 km/hr....................hence solved..

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