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A 8000 kg engine pulls a train of 5 wagons,,each of 2000 kg along a horizontal track .If the engine exerts a force of 40000 N and track offers a friction

force of 5000 N, then calculate<

(a) the net acceleration force (b) the acceleration of train and (c) the force of wagon 1 on wagon 2

Mass of the engine = 8000 kg Mass of each wagon = 2000 kg, Np. of wagons = 5 Total mass of train = 8000+2000×5= 18000 kg Force, F = 40000 N Track resistance , R = 5000 N Total accelerating force = F −R =40000−5000=35000 N Let acceleration = x m/s² Acceleration , = Accelerating force / mass x=35000/18000= 35/18=1.94 m/s² Frictional resistance of 4 wagons = 5000×(2000×4)/18000 =2222 .22 N Accelerating force on 4 wagons =2000×4×1.944 =15552 N Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance =2222 .22 +15552=17774.22 N Total force required to produce acc

Mass of the engine = 8000 kg Mass of each wagon = 2000 kg, Np. of wagons = 5 mass of total wagon=2000*5 =10000 Total mass of train = 8000+2000*5= 18000 kg Force, F = 40000 N Track resistance , R = 5000 N Total accelerating force = F −R =40000−5000 =35000 N Let acceleration = y m/s² Acceleration = Accelerating force / mass y=35000/18000 = 35/18 =1.94 m/s² Frictional resistance of 4 wagons = 5000*(2000*4)/18000 =2222 .22 N Accelerating force on 4 wagons =2000*4*1.944 =15552 N Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance =2222 .22 +15552=17774.22 N

@sweety sorry if said anything wrong but i think we should give answer to help others not for best answer or thanks...even i m new here and i noted that most of people share googled answer....which is not god i think