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A piece wire of resistance 20ohm is drawn out so thatits length is increased to twice its original length calculate the resistance of the wire is the new



If the length of the wire is changed its resistance would obviously change
and we know that resistance is directly proportional too length
Doubling the length will double the resistance, but the wire also must get thinner as it is stretched, because it will contain the same amount of metal in twice the length.
The volume of a cylinder is length * cross sectional area, but in order to find the new cross section, you need to consider what the wire is made of. Most materials resist a change in volume more than they resist a change in shape, and because of that, they lose less volume than otherwise would be expected when stress is applied. In the case of the stretched wire, its density will be less after stretching than it was before. This means that the volume of space occupied by the metal in the wire expands, due to the cross sectional area not shrinking in proportion to the stretch of its length. The amount of reduction in cross section is determined according to Poisson's ratio
Hope this helped u

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