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2 stones are thrown vertically upwards simultaneously with their initial velocity u1 & u2. Prove that the heights reached by them would be in the ratio

u1 square : u2 square. Assume that upward acceleration is -g and downwards acceleration is +g


The distance reached by the stones with velocity u₁ and u₂ is their maximum height.
Hmax for the stone with velocity u₁=u₁²/-2g=-u₁²/2g
Hmax for the stone with velocity u₂=u₂²/-2g=-u₂²/2g
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