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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

The brakes applied to a moving car produce a negative acceleration of 6m/s^2. If the car takes 2s to stop after applying brakes, calculate the distance it

travels during this time.the anser is 12m but i need the steps

V=0 because after applying brakes the car comes to rest. t=2 s a=-6ms⁻² u=? So, we have to find the initial velocity of the car. For this we have to use the first equation of motion. We have; v=u+at 0=u+(-6)x2 0=u-12 u=12 m/s Now to find the distance we can use either the second or third equation of motion. I will show you in both ways By using the second equation, we have: s=ut+1/2.at^2 24+1/2.(-6)x4 24-12=12m By using the third equation, we have: v²-u²=2as 0-144=2x(-6)xs -144=-12s 12s=144 s=12m