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## Answers

It is given that .....................(1)

We also know that [using identities]

So, we can rewrite (1) as +2 = 16 +2

=> = 16

now, =

we know that

So, [1 because ab = ]

Now, substituting values of ( x^{2} + \frac{1}{ x^{2} } + 1) and (x- \frac{1}{x})

We Get :-

Please recheck if there is any mistake in working :-)

The Brainliest Answer!

using identity (a+b)² = a² +2ab +b²

(x)² + 2×x×1/x =18

x² + 2 + 1/x² = 18

x² + 1/x² = 18 - 2

x² + 1/x² = 16

{square rooting both sides}

=

x + = 4

{cubing both the sides}

{ x - }³ = 4³

x³ - - 3×x× { x + } =64

x³ - - 3{4} = 64

x³ - - 12 = 64

x³ - = 64 + 12

therefore x³ + = 76