Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

Given a:b=3:4, then present age of a and b be 3x and 4x given ten years ago, a was half of b => 2(3x X 10) = (4x X 10) => 6x X 20 = 4x X 10 => 2x = 10 => x = 5

Ten years ago let the age of 'a' be 'p' and the age of 'b' be 'q' p=q/2 Now present (p+10)/(q+10) = 3/4 4(p+10) = 3(q+10) 4p+40 = 3q + 30 4p - 3q = 30 - 40 but we know that p = q/2 ⇒2p = q 2(2p) - 3q = -10 2q - 3q = -10 -q = -10 q = 10 the age of 'b' ten years ago was 'q' = 10 now present age of 'b' = q+10 = 10+10 = 20 ten years ago the age of 'a' is p=q/2 = 10/2 = 5 now present age of 'a' is p+10 = 5+10 = 15 therefore the sum of the ages of 'a' and 'b' is 20+15 = 35