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A car gave a reading of distance 2000 km at the start of at trip and 2288km at the end of the trip.

if the trip took 8 hrs ,calculate the average speed of the car in m/s

2]on the 100 m track ,a train travels the first 30 km at the uniform speed of 30km/h.how fast must the train travel the next 70 km so as to average 40 km/h for the entire trip?

Average speed=total distance travelled / total time here total distance will be 288km time taken=8hours =>288/8 =36 km/h =10m/s 2) first 30 km => v = s / t 30 = 30 / t =>t = 1 hr next 70 km let velocity be x v = s / t =>x = 70 /t t = 70 / x total time taken i=> 1 + 70/ x = (70 + x) / x dist. travelled is 100km avg. velovity = total dist / total time 40 = 100|(70 + x) / x => 40. (70+x) / x = 100 2800 + 40x - 100x = 0 => - 60x = - 2800 => x = - 2800 / -60 x = 45.55 km/hr

i have 1 doubt....if the avg speed is 40Km/hr...and the total distance to cover 100Km....so the time taken should be 2.5hrs.....den if the train travels for 1Hr at a speed of 30.....remaining distance is 70Km.....den the train should travel 70Km in 1.5Hrs right.....70/1.5 = 46.667.....