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A bullet is moving at a speed of 300 m/s and strikes a tree. The bullet penetrates for a

distance of 3cm. Determine the acceleration of the bullet while moving into the clay. (Assume a

uniform acceleration.)


Let the deceleration of the bullet inside the tree be a
after covering a distance of 3cm the bullet will be stopped i.e. velocity = 0
initial velocity = 300m/s
so using the formula "v² = u² - 2as"
 v = 0
u = 300m/s
s =  0.03m/s
a = 1500000m/s²
so acceleration of the bullet = -1500000m/s²
0 0 0
v = 0
u = 300m/s
s = 0.03m/s

answer will be  -1500000m/s²
0 0 0
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