Answers

2015-06-10T06:40:56+05:30
Let A be (4,5), B be (7,6) and C be (6,3)

Equation of line AB is given by:-
(x-4)/(4-7) = (y-5)/(5-6)
or, x-4/-3 = y-5/-1
or, -x + 4 = -3y + 15
or, x - 3y +11 = 0

So, 6 - 3*3 + 11 = 17 -9 = 8
So, C does not lie on AB

So, A,B and C are not collinear
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